-3x^2+23=-340

Solution for -3x^2+23=-340 equation:

-3x^2+23=-340

We move all terms to the left:

-3x^2+23-(-340)=0

We add all the numbers together, and all the variables

-3x^2+363=0

a = -3; b = 0; c = +363;
Δ = b2-4ac
Δ = 02-4·(-3)·363
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*-3}=\frac{-66}{-6}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*-3}=\frac{66}{-6}
=-11
$